给你一个整数数组 nums ,找到其中最长严格递增子序列的长度。子序列 是由数组派生而来的序列,删除(或不删除)数组中的元素而不改变其余元素的顺序。例如,[3,6,2,7] 是数组 [0,3,1,6,2,2,7] 的子序列。
暴力求解
var lengthOfLIS = function (nums) {
const n = nums.length
if (n <= 1) {
return n
}
const dp = new Array(n).fill(1)
let max = 1
for (let i = 1; i < n; i++) {
for (let j = i - 1; j >= 0; j--) {
if (nums[i] > nums[j]) {
dp[i] = Math.max(dp[i], dp[j] + 1)
}
}
max = Math.max(dp[i], max)
}
return max
};
优化求解
var lengthOfLIS = function (nums) {
const n = nums.length
if (n <= 1) {
return n
}
const dp = [null, nums[0]]
let max = 1
for (let i = 1; i < n; i++) {
if (dp[max] < nums[i]) {
dp[++max] = nums[i]
continue
}
let pos = 0;
let left = 1,
right = max,
mid;
while (left <= right) {
mid = (left + right) >> 1;
if (nums[i] > dp[mid]) {
left = mid + 1;
pos = mid
} else {
right = mid - 1
}
}
dp[pos + 1] = nums[i]
}
return max
};