一. 需求分析与问题解决
1.1 什么是子查询
子查询指一个查询语句嵌套在另一个查询语句内部的查询,这个特性从MySQL 4.1开始引入。 SQL 中子查询的使用大大增强了 SELECT 查询的能力,因为很多时候查询需要从结果集中获取数据,或者 需要从同一个表中先计算得出一个数据结果,然后与这个数据结果(可能是某个标量,也可能是某个集 合)进行比较。
- 需求举例
#1. 由一个具体的需求,引入子查询
#需求:谁的工资比Abel的高?
#方式1:
SELECT salary
FROM employees
WHERE last_name = 'Abel';
SELECT last_name,salary
FROM employees
WHERE salary > 11000;
#方式2:自连接
SELECT e2.last_name,e2.salary
FROM employees e1,employees e2
WHERE e2.`salary` > e1.`salary` #多表的连接条件
AND e1.last_name = 'Abel';
#方式3:子查询
SELECT last_name,salary
FROM employees
WHERE salary > (
SELECT salary
FROM employees
WHERE last_name = 'Abel'
);
1.2 子查询的基本使用
-
子查询要包含在括号内
-
将子查询放在比较条件的右侧
-
单行操作符对应单行子查询,多行操作符对应多行子查询
-
子查询(内查询)在主查询之前一次执行完成。
-
子查询的结果被主查询(外查询)使用 。
1.3 子查询的分类
-
角度1:从内查询返回的结果的条目数 单行子查询 vs 多行子查询
-
角度2:内查询是否被执行多次 相关子查询 vs 不相关子查询
比如:相关子查询的需求:查询工资大于本部门平均工资的员工信息。 不相关子查询的需求:查询工资大于本公司平均工资的员工信息。
二. 单行子查询
2.1 单行比较操作符
注意:只能在单行子查询中使用(即:只返回一条结果的SELECT查询语句)
2.2 代码示例
#题目:查询工资大于149号员工工资的员工的信息
SELECT employee_id,last_name,salary
FROM employees
WHERE salary > (
SELECT salary
FROM employees
WHERE employee_id = 149
);
#题目:返回job_id与141号员工相同,salary比143号员工多的员工姓名,job_id和工资
SELECT last_name,job_id,salary
FROM employees
WHERE job_id = (
SELECT job_id
FROM employees
WHERE employee_id = 141
)
AND salary > (
SELECT salary
FROM employees
WHERE employee_id = 143
);
#题目:返回公司工资最少的员工的last_name,job_id和salary
SELECT last_name,job_id,salary
FROM employees
WHERE salary = (
SELECT MIN(salary)
FROM employees
);
#题目:查询与141号员工的manager_id和department_id相同的其他员工
#的employee_id,manager_id,department_id。
#方式1:
SELECT employee_id,manager_id,department_id
FROM employees
WHERE manager_id = (
SELECT manager_id
FROM employees
WHERE employee_id = 141
)
AND department_id = (
SELECT department_id
FROM employees
WHERE employee_id = 141
)
AND employee_id <> 141;
#方式2:了解
SELECT employee_id,manager_id,department_id
FROM employees
WHERE (manager_id,department_id) = (
SELECT manager_id,department_id
FROM employees
WHERE employee_id = 141
)
AND employee_id <> 141;
2.3 HAVING 中的子查询
#题目:查询最低工资大于110号部门最低工资的部门id和其最低工资
SELECT department_id,MIN(salary)
FROM employees
WHERE department_id IS NOT NULL
GROUP BY department_id
HAVING MIN(salary) > (
SELECT MIN(salary)
FROM employees
WHERE department_id = 110
);
2.4 CASE中的子查询
#题目:显式员工的employee_id,last_name和location。
#其中,若员工department_id与location_id为1800的department_id相同,
#则location为’Canada’,其余则为’USA’。
SELECT employee_id,last_name,CASE department_id WHEN (SELECT department_id FROM departments WHERE location_id = 1800) THEN 'Canada'
ELSE 'USA' END "location"
FROM employees;
2.5 子查询中的空值问题
#4.2 子查询中的空值问题
SELECT last_name, job_id
FROM employees
WHERE job_id =
(SELECT job_id
FROM employees
WHERE last_name = 'Haas');
2.5 非法使用子查询
#4.3 非法使用子查询
#错误:Subquery returns more than 1 row
SELECT employee_id, last_name
FROM employees
WHERE salary =
(SELECT MIN(salary)
FROM employees
GROUP BY department_id);
三. 多行子查询
- 也称为集合比较子查询
- 内查询返回多行
- 使用多行比较操作符
3.1 多行比较操作符
3.2 代码示例
#5.1 多行子查询的操作符: IN ANY ALL SOME(同ANY)
#5.2举例:
# IN:
SELECT employee_id, last_name
FROM employees
WHERE salary IN
(SELECT MIN(salary)
FROM employees
GROUP BY department_id);
# ANY / ALL:
#题目:返回其它job_id中比job_id为‘IT_PROG’部门任一工资低的员工的员工号、
#姓名、job_id 以及salary
SELECT employee_id,last_name,job_id,salary
FROM employees
WHERE job_id <> 'IT_PROG'
AND salary < ANY (
SELECT salary
FROM employees
WHERE job_id = 'IT_PROG'
);
#题目:返回其它job_id中比job_id为‘IT_PROG’部门所有工资低的员工的员工号、
#姓名、job_id 以及salary
SELECT employee_id,last_name,job_id,salary
FROM employees
WHERE job_id <> 'IT_PROG'
AND salary < ALL (
SELECT salary
FROM employees
WHERE job_id = 'IT_PROG'
);
#题目:查询平均工资最低的部门id
#MySQL中聚合函数是不能嵌套使用的。
#方式1:
SELECT department_id
FROM employees
GROUP BY department_id
HAVING AVG(salary) = (
SELECT MIN(avg_sal)
FROM(
SELECT AVG(salary) avg_sal
FROM employees
GROUP BY department_id
) t_dept_avg_sal
);
#方式2:
SELECT department_id
FROM employees
GROUP BY department_id
HAVING AVG(salary) <= ALL(
SELECT AVG(salary) avg_sal
FROM employees
GROUP BY department_id
)
3.3 空值问题
#5.3 空值问题
SELECT last_name
FROM employees
WHERE employee_id NOT IN (
SELECT manager_id
FROM employees
);
四. 相关子查询
如果子查询的执行依赖于外部查询,通常情况下都是因为子查询中的表用到了外部的表,并进行了条件 关联,因此每执行一次外部查询,子查询都要重新计算一次,这样的子查询就称之为 关联子查询 。 相关子查询按照一行接一行的顺序执行,主查询的每一行都执行一次子查询。
简而言之,就是在内查询中使用了外查询中的表
4.1 代码示例
#回顾:查询员工中工资大于公司平均工资的员工的last_name,salary和其department_id
#6.1
SELECT last_name,salary,department_id
FROM employees
WHERE salary > (
SELECT AVG(salary)
FROM employees
);
#题目:查询员工中工资大于本部门平均工资的员工的last_name,salary和其department_id
#方式1:使用相关子查询
SELECT last_name,salary,department_id
FROM employees e1
WHERE salary > (
SELECT AVG(salary)
FROM employees e2
WHERE department_id = e1.`department_id`
);
#方式2:在FROM中声明子查询
SELECT e.last_name,e.salary,e.department_id
FROM employees e,(
SELECT department_id,AVG(salary) avg_sal
FROM employees
GROUP BY department_id) t_dept_avg_sal
WHERE e.department_id = t_dept_avg_sal.department_id
AND e.salary > t_dept_avg_sal.avg_sal
#题目:查询员工的id,salary,按照department_name 排序
SELECT employee_id,salary
FROM employees e
ORDER BY (
SELECT department_name
FROM departments d
WHERE e.`department_id` = d.`department_id`
) ASC;
#题目:若employees表中employee_id与job_history表中employee_id相同的数目不小于2,
#输出这些相同id的员工的employee_id,last_name和其job_id
SELECT *
FROM job_history;
SELECT employee_id,last_name,job_id
FROM employees e
WHERE 2 <= (
SELECT COUNT(*)
FROM job_history j
WHERE e.`employee_id` = j.`employee_id`
)
结论:在SELECT中,除了GROUP BY 和 LIMIT之外,其他位置都可以声明子查询!
4.3 EXISTS 与 NOT EXISTS关键字
- 关联子查询通常也会和 EXISTS操作符一起来使用,用来检查在子查询中是否存在满足条件的行。
- 如果在子查询中不存在满足条件的行:
- 条件返回 FALSE
- 继续在子查询中查找
- 如果在子查询中存在满足条件的行:
- 不在子查询中继续查找
- 条件返回 TRUE
- NOT EXISTS关键字表示如果不存在某种条件,则返回TRUE,否则返回FALSE。
- 代码演示
#题目:查询公司管理者的employee_id,last_name,job_id,department_id信息
#方式1:自连接
SELECT DISTINCT mgr.employee_id,mgr.last_name,mgr.job_id,mgr.department_id
FROM employees emp JOIN employees mgr
ON emp.manager_id = mgr.employee_id;
#方式2:子查询
SELECT employee_id,last_name,job_id,department_id
FROM employees
WHERE employee_id IN (
SELECT DISTINCT manager_id
FROM employees
);
#方式3:使用EXISTS
SELECT employee_id,last_name,job_id,department_id
FROM employees e1
WHERE EXISTS (
SELECT *
FROM employees e2
WHERE e1.`employee_id` = e2.`manager_id`
);
#题目:查询departments表中,不存在于employees表中的部门的department_id和department_name
#方式1:
SELECT d.department_id,d.department_name
FROM employees e RIGHT JOIN departments d
ON e.`department_id` = d.`department_id`
WHERE e.`department_id` IS NULL;
#方式2:
SELECT department_id,department_name
FROM departments d
WHERE NOT EXISTS (
SELECT *
FROM employees e
WHERE d.`department_id` = e.`department_id`
);
SELECT COUNT(*)
FROM departments;