[剑指offer09]用两个栈实现队列

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刷剑指offer的第一天第一题

题目:用两个栈实现队列

用两个栈实现一个队列。队列的声明如下,请实现它的两个函数 appendTail 和 deleteHead ,分别完成在队列尾部插入整数和在队列头部删除整数的功能。(若队列中没有元素,deleteHead 操作返回 -1 )

示例 1:

输入: ["CQueue","appendTail","deleteHead","deleteHead"] [[],[3],[],[]] 输出:[null,null,3,-1]

示例 2:

输入: ["CQueue","deleteHead","appendTail","appendTail","deleteHead","deleteHead"] [[],[],[5],[2],[],[]] 输出:[null,-1,null,null,5,2]

基本思路: 1.定义两个栈starckA和starckB,分别为入队栈和出队栈(栈:先进后出;队列:先进先出) 2.appendTail操作即放到入队栈中(直接用push) 3.deleteHead则从出队栈中拿,先判断出队栈是否为空,如果为空则从入队栈放入,都为空则返回-1

上代码:

var CQueue = function() {
this.starckA = []
this.starckB = []
};

/** 
 * @param {number} value
 * @return {void}
 */
CQueue.prototype.appendTail = function(value) {
    this.starckA.push(value)
};

/**
 * @return {number}
 */
CQueue.prototype.deleteHead = function() {
if(!this.starckB.length){
    if(!this.starckA.length){
        return -1
    }
    while(this.starckA.length){
        this.starckB.push(this.starckA.pop()) //入队栈放入出队栈 
    }
        return this.starckB.pop()
}else{
    return this.starckB.pop()
}

图片.png

题目链接:leetcode-cn.com/problems/yo…