题目
leetcode-cn.com/problems/im…

思路
- indexOf
- 循环遍历(即便是indexOf一秒解决但还是要正常考虑的是屑x
题解
var strStr = function(haystack, needle) { return haystack.indexOf(needle) };
var strStr = function(haystack, needle) {
if (needle == '') return 0
if (needle.length > haystack.length) return -1
var i, j;
for (i = 0; i < haystack.length; i++) {
if (needle.charAt(0) == haystack.charAt(i)) {
for (j = 1; j < needle.length; j++)
if (needle.charAt(j) != haystack.charAt(i + j)) break
if (j == needle.length) return i
}
}
return -1
};