方法一:indexOf()
var arr1 = [1,5,2,3,4,2,3,1,3,4];
var arr2 = [];
for(var i=0; i<arr1.length; i++){
if(arr1.indexOf(arr1[i]) == i){
arr2.push(arr1[i])
}
}
console.log(arr2)
方法二:ES6 set
var arr1 = [1,5,2,3,4,2,3,1,3,4];
var arr2 = new Set(arr1);
console.log([...arr2])
方法三:reduce
let arr=[1,5,2,3,4,2,3,1,3,4];
let result=arr.reduce((prev,cur,index,arr)=>{
prev.indexOf(cur)===-1?prev.push(cur):prev;
return prev;
},[])
console.log(result);
方法四:include
let arr=[1,5,2,3,4,2,3,1,3,4];
var newArr=[];
for(var i in arr){
if(!newArr.includes(arr[i])){
newArr.push(arr[i])
}
}
console.log(newArr)
方法五:map
let arr=[1,5,2,3,4,2,3,1,3,4];
const map = new Map();
arr.filter((item)=>!map.has(item)&&map.set(item,1))