这个题跟我之前写的js(65)~[692] 前K个高频单词,基本上一模一样,但是我觉得上一次看的写法不是和好理解,所以又看了很多个解析,找到了一个更好力理解的方法,本来是准备把它改造成一个通用的又没哟改造成功
先上正确代码
/**
* @param {number[]} nums
* @param {number} k
* @return {number[]}
*/
var topKFrequent = function(nums, k) {
const map = new Map();
for(const num of nums) {
map.set(num, (map.get(num) || 0) + 1);
}
// 创建小顶堆
const priorityQueue = new PriorityQueue((a, b) => a[1] - b[1]);
// entry 是一个长度为2的数组,0位置存储key,1位置存储value
for (const entry of map.entries()) {
priorityQueue.push(entry);
if (priorityQueue.size() > k) {
priorityQueue.pop();
}
}
const ret = [];
for(let i = priorityQueue.size() - 1; i >= 0; i--) {
ret[i] = priorityQueue.pop()[0];
}
return ret;
};
function PriorityQueue(compareFn) {
this.compareFn = compareFn;
this.queue = [];
}
// 添加
PriorityQueue.prototype.push = function(item) {
this.queue.push(item);
let index = this.queue.length - 1;
let parent = Math.floor((index - 1) / 2);
// 上浮
while(parent >= 0 && this.compare(parent, index) > 0) {
// 交换
[this.queue[index], this.queue[parent]] = [this.queue[parent], this.queue[index]];
index = parent;
parent = Math.floor((index - 1) / 2);
}
}
// 获取堆顶元素并移除
PriorityQueue.prototype.pop = function() {
const ret = this.queue[0];
// 把最后一个节点移到堆顶
this.queue[0] = this.queue.pop();
let index = 0;
// 左子节点下标,left + 1 就是右子节点下标
let left = 1;
let selectedChild = this.compare(left, left + 1) > 0 ? left + 1 : left;
// 下沉
while(selectedChild !== undefined && this.compare(index, selectedChild) > 0) {
// 交换
[this.queue[index], this.queue[selectedChild]] = [this.queue[selectedChild], this.queue[index]];
index = selectedChild;
left = 2 * index + 1;
selectedChild = this.compare(left, left + 1) > 0 ? left + 1 : left;
}
return ret;
}
PriorityQueue.prototype.size = function() {
return this.queue.length;
}
// 使用传入的 compareFn 比较两个位置的元素
PriorityQueue.prototype.compare = function(index1, index2) {
if (this.queue[index1] === undefined) {
return 1;
}
if (this.queue[index2] === undefined) {
return -1;
}
return this.compareFn(this.queue[index1], this.queue[index2]);
}
下面是我改造的代码,失败的,除此我还有按照之前我经常写的大顶堆和小顶堆尝试解决本题,也是没有成功,代码在最后
/**
* @param {number[]} nums
* @param {number} k
* @return {number[]}
*/
/**
* @param {number[]} nums
* @param {number} k
* @return {number[]}
*/
var topKFrequent = function(nums, k) {
const map = new Map();
for(const num of nums) {
map.set(num, (map.get(num) || 0) + 1);
}
// 创建小顶堆
const priorityQueue = new PriorityQueue();
// entry 是一个长度为2的数组,0位置存储key,1位置存储value
for (const entry of map.entries()) {
priorityQueue.push(entry);
if (priorityQueue.size() > k) {
priorityQueue.pop();
}
}
const ret = [];
for(let i = priorityQueue.size() - 1; i >= 0; i--) {
ret[i] = priorityQueue.pop()[0];
}
return ret;
};
const cmp = (a, b) => a[1] < b[1];
function PriorityQueue(compareFn = cmp) {
this.compare = compareFn;
this.queue = [];
}
// 添加
PriorityQueue.prototype.push = function(item) {
this.queue.push(item);
let index = this.queue.length - 1;
let parent = Math.floor((index - 1) / 2);
// 上浮
while(parent >= 0 && this.compare(this.queue[parent], this.queue[index]) ) {
// 交换
[this.queue[index], this.queue[parent]] = [this.queue[parent], this.queue[index]];
index = parent;
parent = Math.floor((index - 1) / 2);
}
}
// 获取堆顶元素并移除
PriorityQueue.prototype.pop = function() {
const ret = this.queue[0];
// 把最后一个节点移到堆顶
this.queue[0] = this.queue.pop();
let index = 0;
// 左子节点下标,left + 1 就是右子节点下标
let left = 1;
let selectedChild = this.compare(this.queue[left], this.queue[left+ 1])
? left : left + 1;
// 下沉
while(selectedChild !== undefined && this.compare(this.queue[selectedChild],this.queue[index] ) ) {
// 交换
[this.queue[index], this.queue[selectedChild]] = [this.queue[selectedChild], this.queue[index]];
index = selectedChild;
left = 2 * index + 1;
selectedChild = this.compare(this.queue[left], this.queue[left+ 1]) ? left : left+1;
}
return ret;
}
PriorityQueue.prototype.size = function() {
return this.queue.length;
}
// 使用传入的 compareFn 比较两个位置的元素
// PriorityQueue.prototype.compare = function(index1, index2) {
// if (this.queue[index1] === undefined) {
// return 1;
// }
// if (this.queue[index2] === undefined) {
// return -1;
// }
// return this.compareFn(this.queue[index1], this.queue[index2]);
// }
另外一种错误代码
/*
* @lc app=leetcode.cn id=347 lang=javascript
*
* [347] 前 K 个高频元素
*/
// @lc code=start
/**
* @param {number[]} nums
* @param {number} k
* @return {number[]}
*/
var topKFrequent = function (nums, k) {
let map = new Map();
let heap = [];
// 1 生成一个map先统计nums每个数出现的频次
nums.forEach(item => {
map.has(item) ? map.set(item, map.get(item) + 1) : map.set(item, 1)
})
const minHeap = new Heap();
console.log(minHeap);
for (const item of map.entries()) {
minHeap.insert(item);
console.log(minHeap.arr.length,'k', k);
if (minHeap.arr.length > k) {
minHeap.pop();
}
}
console.log(minHeap, '-----', minHeap.arr)
const res = [];
for(let i = minHeap.arr.length - 1; i >= 0; i--) {
res[i] = minHeap.pop()[0];
}
return res;
};
const swap = (arr, i, j) => ([arr[i], arr[j]] = [arr[j], arr[i]]);
const defaultCmp = (a, b) => (a[1] < b[1]);
class Heap {
constructor(cmp = defaultCmp) {
this.arr = [];
this.cmp = cmp;
}
insert(v) {
this.arr.push(v);
let i = this.arr.length - 1;
while (i) {
let parent = i - 1 >> 1;
if (this.cmp(i, parent)) {
swap(this.arr, i, parent)
i = parent;
}
}
}
pop() {
const len = this.arr.length;
swap(this.arr, 0, i);
const res = this.arr.pop();
let i = 0;
let exchange = 2 * i + 1;
while (exchange < len) {
let r = 2 * i + 2;
if (r < len && this.cmp(arr[r], arr[exchange])) {
exchange = r;
}
if (this.cmp(exchange, i)) {
swap(this.arr, i, exchange);
i = exchange;
exchange = 2 * i + 1;
} else {
break;
}
}
return res;
}
}
// @lc code=end