题目描述
分析
把所有的链表头节点放到堆中
每次取出 val 最小的节点
重新构建链表
算法
堆
过程
手写一个堆
将所有的节点放到堆里
不断地从堆中弹出节点
构建新的链表
判断是否有后继,有的话放到堆里
代码
/**
* Definition for singly-linked list.
* function ListNode(val, next) {
* this.val = (val===undefined ? 0 : val)
* this.next = (next===undefined ? null : next)
* }
*/
/**
* @param {ListNode[]} lists
* @return {ListNode}
*/
var mergeKLists = function (lists) {
const h = new Heap((a, b) => {
if (!b) return false
return a.val > b.val
})
const ret = new ListNode()
let p = ret
for (const x of lists) {
if (!x) continue
h.insert(x)
}
while (!h.isEmpty()) {
const cur = h.extract()
p.next = cur
if (cur.next) {
h.insert(cur.next)
}
p = p.next
}
return ret.next
}
class Heap {
constructor(compareFn) {
this.compareFn = compareFn
this.heap = []
}
swap(parent, index) {
const arr = this.heap
;[arr[parent], arr[index]] = [arr[index], arr[parent]]
}
getLeftIndex(index) {
return index * 2 + 1
}
getRightIndex(index) {
return index * 2 + 2
}
getParentIndex(index) {
return Math.floor((index - 1) / 2)
}
size() {
return this.heap.length
}
isEmpty() {
return this.size() === 0
}
insert(value) {
const index = this.heap.length
this.heap.push(value)
this.siftUp(index)
}
siftUp(index) {
let parent = this.getParentIndex(index)
while (index > 0 && this.compareFn(this.heap[parent], this.heap[index])) {
this.swap(parent, index)
index = parent
parent = this.getParentIndex(index)
}
}
extract() {
if (this.isEmpty()) return
if (this.size() === 1) return this.heap.pop()
const removedItem = this.heap[0]
this.heap[0] = this.heap.pop()
this.siftDown(0)
return removedItem
}
siftDown(index) {
let element = index
const left = this.getLeftIndex(index)
const right = this.getRightIndex(index)
if (
index < this.size() &&
this.compareFn(this.heap[element], this.heap[left])
) {
element = left
}
if (
index < this.size() &&
this.compareFn(this.heap[element], this.heap[right])
) {
element = right
}
if (element !== index) {
this.swap(element, index)
this.siftDown(element)
}
}
top() {
return this.heap[0]
}
}