异步函数返回异步函数的值，不需要在内部await

const fn = async ()=>{
    return 111;
}
const fn1 = async ()=>
    return fn();
}
const fn2 = async ()=>{
    return await fn();
}
const print = async ()=>{
    console.log('fn1: ', await fn1());
    console.log('fn2: ', await fn2());
}

print();

输出结果都是：111