要求
给你一棵二叉树的根节点 root ,请你返回 层数最深的叶子节点的和 。
示例 1:
输入:root = [1,2,3,4,5,null,6,7,null,null,null,null,8]
输出:15
示例 2:
输入:root = [6,7,8,2,7,1,3,9,null,1,4,null,null,null,5]
输出:19
提示:
- 树中节点数目在范围 [1, 104] 之间。
- 1 <= Node.val <= 100
核心代码
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def deepestLeavesSum(self, root: Optional[TreeNode]) -> int:
from collections import deque
if not root:
return 0
queue = deque([root])
while queue:
res = []
for _ in range(len(queue)):
node = queue.popleft()
res.append(node.val)
if node.left:
queue += [node.left]
if node.right:
queue += [node.right]
return sum(res)
解题思路:这个题就是广度优先遍历,我们存储每一层的值,最终得到最后一层,将所有值加和即可。