var solution = function(isBadVersion) {
/**
* @param {integer} n Total versions
* @return {integer} The first bad version
*/
return function(n) {
let left = 1, right = n;
while (left < right) { // 循环直至区间左右端点相同
const mid = Math.floor(left + (right - left) / 2); // 防止计算时溢出
if (isBadVersion(mid)) {
right = mid; // 答案在区间 [left, mid] 中
} else {
left = mid + 1; // 答案在区间 [mid+1, right] 中
}
}
// 此时有 left == right,区间缩为一个点,即为答案
return left;
};
};