>三升序列<
对于一个字母矩阵,我们称矩阵中的一个三升序列是指在矩阵中找到三个字母,它们在 同一行,同一列,或者在同一 45 度的斜线上,这三个字母从左向右看、或者从上向下看是 递增的。
例如,如下矩阵中
YQPD
BKEZ
AFYV
有 BKZ、BEZ、AFY、AFV、AKP、DEF 等 6 个三升序列。注意当三个字母是从左下到右上排 列时,从左向右看和从上向下看是不同的顺序。
对于下面的 30 行 50 列的矩阵,请问总共有多少个三升序列?
VLPWJVVNNZSWFGHSFRBCOIJTPYNEURPIGKQGPSXUGNELGRVZAG
SDLLOVGRTWEYZKKXNKIRWGZWXWRHKXFASATDWZAPZRNHTNNGQF
ZGUGXVQDQAEAHOQEADMWWXFBXECKAVIGPTKTTQFWSWPKRPSMGA
BDGMGYHAOPPRRHKYZCMFZEDELCALTBSWNTAODXYVHQNDASUFRL
YVYWQZUTEPFSFXLTZBMBQETXGXFUEBHGMJKBPNIHMYOELYZIKH
ZYZHSLTCGNANNXTUJGBYKUOJMGOGRDPKEUGVHNZJZHDUNRERBU
XFPTZKTPVQPJEMBHNTUBSMIYEGXNWQSBZMHMDRZZMJPZQTCWLR
ZNXOKBITTPSHEXWHZXFLWEMPZTBVNKNYSHCIQRIKQHFRAYWOPG
MHJKFYYBQSDPOVJICWWGGCOZSBGLSOXOFDAADZYEOBKDDTMQPA
VIDPIGELBYMEVQLASLQRUKMXSEWGHRSFVXOMHSJWWXHIBCGVIF
GWRFRFLHAMYWYZOIQODBIHHRIIMWJWJGYPFAHZZWJKRGOISUJC
EKQKKPNEYCBWOQHTYFHHQZRLFNDOVXTWASSQWXKBIVTKTUIASK
PEKNJFIVBKOZUEPPHIWLUBFUDWPIDRJKAZVJKPBRHCRMGNMFWW
CGZAXHXPDELTACGUWBXWNNZNDQYYCIQRJCULIEBQBLLMJEUSZP
RWHHQMBIJWTQPUFNAESPZHAQARNIDUCRYQAZMNVRVZUJOZUDGS
PFGAYBDEECHUXFUZIKAXYDFWJNSAOPJYWUIEJSCORRBVQHCHMR
JNVIPVEMQSHCCAXMWEFSYIGFPIXNIDXOTXTNBCHSHUZGKXFECL
YZBAIIOTWLREPZISBGJLQDALKZUKEQMKLDIPXJEPENEIPWFDLP
HBQKWJFLSEXVILKYPNSWUZLDCRTAYUUPEITQJEITZRQMMAQNLN
DQDJGOWMBFKAIGWEAJOISPFPLULIWVVALLIIHBGEZLGRHRCKGF
LXYPCVPNUKSWCCGXEYTEBAWRLWDWNHHNNNWQNIIBUCGUJYMRYW
CZDKISKUSBPFHVGSAVJBDMNPSDKFRXVVPLVAQUGVUJEXSZFGFQ
IYIJGISUANRAXTGQLAVFMQTICKQAHLEBGHAVOVVPEXIMLFWIYI
ZIIFSOPCMAWCBPKWZBUQPQLGSNIBFADUUJJHPAIUVVNWNWKDZB
HGTEEIISFGIUEUOWXVTPJDVACYQYFQUCXOXOSSMXLZDQESHXKP
FEBZHJAGIFGXSMRDKGONGELOALLSYDVILRWAPXXBPOOSWZNEAS
VJGMAOFLGYIFLJTEKDNIWHJAABCASFMAKIENSYIZZSLRSUIPCJ
BMQGMPDRCPGWKTPLOTAINXZAAJWCPUJHPOUYWNWHZAKCDMZDSR
RRARTVHZYYCEDXJQNQAINQVDJCZCZLCQWQQIKUYMYMOVMNCBVY
ABTCRRUXVGYLZILFLOFYVWFFBZNFWDZOADRDCLIRFKBFBHMAXX
说明:
1.见上详述
一、解题思路
1、解法一( Java )
解法思路:进行 深度搜索 判断是否符合即可。
代码如下:
import java.util.Scanner;
public class Sequence {
static char[][] chs = new char[30][50];
static int[][] dir = { { 0, 1 }, { 1, 0 }, { 1, 1 }, { 1, -1 }, { -1, 1 } };
static int cnt = 0;
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
for (int i = 0; i < 30; i++) {
String str = scan.next();
for (int j = 0; j < 50; j++) {
chs[i][j] = str.charAt(j);
}
}
int ia, ib, iaa, ibb;
for (int i = 0; i < 30; i++) {
for (int j = 0; j < 50; j++) {
for (int k = 0; k < 5; k++) {
ia = i;
ib = j;
while (true) {
ia += dir[k][0];
ib += dir[k][1];
iaa = ia;
ibb = ib;
if (ia < 0 || ib < 0 || ia >= 30 || ib >= 50) {
break;
}
while (true) {
iaa += dir[k][0];
ibb += dir[k][1];
if (iaa < 0 || ibb < 0 || iaa >= 30 || ibb >= 50) {
break;
}
if (chs[i][j] < chs[ia][ib] && chs[ia][ib] < chs[iaa][ibb]) {
cnt++;
}
}
}
}
}
}
System.out.println(cnt);
scan.close();
}
}
运行结果截图如下: