LeetCode-007整数反转

57 阅读1分钟
public int reverse(int x) {

    String s = String.valueOf(x); //整数转字符串
    int len = s.length();
    int zs = len;
    if(s.charAt(0)=='-'){ //判断正负
        zs = len-1;
    }
    String temp = "";
    for(int i=0;i<zs;i++){ //倒叙
        temp = temp + s.charAt(len-i-1);
    }
    int res = 0;
    try { //处理异常 超过int的范围返回0
        if(zs==len-1){
            res = 0-Integer.parseInt(temp);
        }else{
            res = Integer.parseInt(temp);
        }
    }catch (Exception e){
        return 0;
    }
    return res;
}

 

 

反正就很暴力 优化代码见github