poj2080--算日期

题意：起始日期为2001-1-1，求过了那天后的日期还有那天是周几。

思路：最重要的是判断闰年，加一个判断函数，之后周几对7取余数就知道了。

#include <iostream>
using namespace std; 
int mon[2][13]={0,31,28,31,30,31,30,31,31,30,31,30,31,0,31,29,31,30,31,30,31,31,30,31,30,31};
int yea[2]={365,366};
int n;
char zhou[7][15]={"Saturday","Sunday","Monday", "Tuesday", "Wednesday", "Thursday", "Friday"};

/* run this program using the console pauser or add your own getch, system("pause") or input loop */
int judge(int y){
	if((y%400==0)||(y%4==0&&y%100!=0))
	return 1;
	else return 0;
}

int main(int argc, char** argv) {
	while(cin>>n&&n!=-1){
		int i,j,day=1;
		int ff=n%7;
		for(i=2000;n>=yea[judge(i)];i++)
			n-=yea[judge(i)];
		int tt=judge(i);
		for(j=1;n>=mon[tt][j];j++)
			n-=mon[tt][j];
		day+=n;
		printf("%d-%02d-%02d %s\n",i,j,day,zhou[ff]);
		
	} 
	
	return 0;
}