题目
Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.
Input Specification: Each input file contains one test case. Each case is given in the following format:
N name[1] ID[1] grade[1] name[2] ID[2] grade[2] ... ... name[N] ID[N] grade[N] grade1 grade2 where name[i] and ID[i] are strings of no more than 10 characters with no space, grade[i] is an integer in [0, 100], grade1 and grade2 are the boundaries of the grade's interval. It is guaranteed that all the grades are distinct.
Output Specification: For each test case you should output the student records of which the grades are in the given interval [grade1, grade2] and are in non-increasing order. Each student record occupies a line with the student's name and ID, separated by one space. If there is no student's grade in that interval, output NONE instead.
Sample Input 1:
4
Tom CS000001 59
Joe Math990112 89
Mike CS991301 100
Mary EE990830 95
60 100
结尾无空行
Sample Output 1:
Mike CS991301
Mary EE990830
Joe Math990112
结尾无空行
Sample Input 2:
2
Jean AA980920 60
Ann CS01 80
90 95
结尾无空行
Sample Output 2:
NONE
结尾无空行
解题思路
N = int(input())
# N = int("4")
inputList = []
for _ in range(N):
name, ID, grade = map(str,input().split())
# name, ID, grade = map(str, "Joe Math990112 89".split())
inputList.append([name,ID,int(grade)])
grade1, grade2 = map(int,input().split())
# grade1, grade2 = map(int,"60 100".split())
resList = []
for each in inputList:
if each[2]>= grade1 and each[2] <= grade2:
resList.append(each)
# 排序输出
resList.sort(key=lambda x:-x[2])
if len(resList) == 0:
print("NONE")
else:
for each in resList:
print(each[0],each[1])
