var maxarr = [1, 3, 45, 43, 5, 45, 100]
function findmax1(maxarr) {
return Math.max(...maxarr)
}
function findmax2(maxarr) {
var number = maxarr[0];
for (var i = 1; i < maxarr.length; i++) {
number < maxarr[i] && (number = maxarr[i])
}
return number
}
function findmax3(maxarr) {
return maxarr.sort((a, b) => b - a)[0]
}