leetcode 705. Design HashSet(python)

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描述

Design a HashSet without using any built-in hash table libraries.

Implement MyHashSet class:

  • void add(key) Inserts the value key into the HashSet.
  • bool contains(key) Returns whether the value key exists in the HashSet or not.
  • void remove(key) Removes the value key in the HashSet. If key does not exist in the HashSet, do nothing.

Example 1:

Input
["MyHashSet", "add", "add", "contains", "contains", "add", "contains", "remove", "contains"]
[[], [1], [2], [1], [3], [2], [2], [2], [2]]
Output
[null, null, null, true, false, null, true, null, false]

Explanation
MyHashSet myHashSet = new MyHashSet();
myHashSet.add(1);      // set = [1]
myHashSet.add(2);      // set = [1, 2]
myHashSet.contains(1); // return True
myHashSet.contains(3); // return False, (not found)
myHashSet.add(2);      // set = [1, 2]
myHashSet.contains(2); // return True
myHashSet.remove(2);   // set = [1]
myHashSet.contains(2); // return False, (already removed)

Note:

0 <= key <= 10^6
At most 104 calls will be made to add, remove, and contains.

解析

根据题意,就是实现一个 Hashset ,直接使用列表的相关操作即可实现,很简单,不再赘述。这种方法使用了内置函数,不推荐使用。

解答

class MyHashSet(object):

    def __init__(self):
        """
        Initialize your data structure here.
        """
        self.l = []
    def add(self, key):
        """
        :type key: int
        :rtype: None
        """
        if key not in self.l:
            self.l.append(key)

    def remove(self, key):
        """
        :type key: int
        :rtype: None
        """
        if key in self.l:
            self.l.remove(key)
        
    def contains(self, key):
        """
        Returns true if this set contains the specified element
        :type key: int
        :rtype: bool
        """
        if key in self.l:
            return True
        return False



        	      
		

运行结果

Runtime: 1104 ms, faster than 25.11% of Python online submissions for Design HashSet.
Memory Usage: 18.3 MB, less than 85.65% of Python online submissions for Design HashSet.

解析

另外一种思路就是初始化一个数组,因为上面限制了 key 的长度在 10^6 之内,所以数组的长度设置成 1000001 ,全部都设置为 False ,如果有数字就设置为 True ,利用数组的基本操作完成题目中的各个函数功能。

解答

class MyHashSet(object):

    def __init__(self):
        """
        Initialize your data structure here.
        """
        self.set = [False] * 1000001
    def add(self, key):
        """
        :type key: int
        :rtype: None
        """
        self.set[key] = True

    def remove(self, key):
        """
        :type key: int
        :rtype: None
        """
        self.set[key] = False
        
    def contains(self, key):
        """
        Returns true if this set contains the specified element
        :type key: int
        :rtype: bool
        """
        return self.set[key]

运行结果

Runtime: 356 ms, faster than 35.60% of Python online submissions for Design HashSet.
Memory Usage: 41.2 MB, less than 5.18% of Python online submissions for Design HashSet.

原题链接:leetcode.com/problems/de…

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