给定一个二叉树,在树的最后一行找到最左边的值。
代码
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
int maxL=0,maxN=0;
public int findBottomLeftValue(TreeNode root) {
BottomLeft(root,1);
return maxN;
}
public void BottomLeft(TreeNode root,int level) {//先序遍历
if(root==null) return;
if(maxL<level)//如果找出更深的节点,替换掉
{
maxL=level;
maxN=root.val;
}
BottomLeft(root.left,level+1);
BottomLeft(root.right,level+1);
}
}