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描述
Hercy wants to save money for his first car. He puts money in the Leetcode bank every day.
He starts by putting in $1 on Monday, the first day. Every day from Tuesday to Sunday, he will put in $1 more than the day before. On every subsequent Monday, he will put in $1 more than the previous Monday.
Given n, return the total amount of money he will have in the Leetcode bank at the end of the nth day.
Example 1:
Input: n = 4
Output: 10
Explanation: After the 4th day, the total is 1 + 2 + 3 + 4 = 10.
Example 2:
Input: n = 10
Output: 37
Explanation: After the 10th day, the total is (1 + 2 + 3 + 4 + 5 + 6 + 7) + (2 + 3 + 4) = 37. Notice that on the 2nd Monday, Hercy only puts in $2.
Example 3:
Input: n = 20
Output: 96
Explanation: After the 20th day, the total is (1 + 2 + 3 + 4 + 5 + 6 + 7) + (2 + 3 + 4 + 5 + 6 + 7 + 8) + (3 + 4 + 5 + 6 + 7 + 8) = 96.
Note:
1 <= n <= 1000
解析
根据题意，就是第一周按照【1，2，3，4，5，6，7】的方式存钱，第二周按照【2，3，4，5，6，7，8】的方式存钱，第三周按照【3，4，5，6，7，8，9】，第四周按照【4，5，6，7，8，9，10】等等规律。以此类推，这就是一个找规律的题目，找出规律就会写代码了。
解答
class Solution(object):
def totalMoney(self, n):
"""
:type n: int
:rtype: int
"""
result = 0
base = 1
for i in range(1, n+1):
if i%7:
result += (base-1)+i%7
else:
result += base+(i-1)%7
base += 1
return result
运行结果
Runtime: 28 ms, faster than 23.66% of Python online submissions for Calculate Money in Leetcode Bank.
Memory Usage: 13.4 MB, less than 28.12% of Python online submissions for Calculate Money in Leetcode Bank.
思考
这个题给了我一个思考，加入我是这个人 Hercy ，我想自己买车，也按照他这种方式存钱，我得需要多少周的时间才能完成，我的理想是买一辆野马，需要 40 万左右，下面开始写代码。
解答
def cal(n):
result = 0
base = [1,2,3,4,5,6,7]
for i in range(n//sum(base)):
t = sum(base) + i * 7
result += t
print('这是第%d周，这周攒了%d元，累计攒了%d元'%(i+1,t,result))
if result >= n:
return i+1
运行结果
...
这是第331周，这周攒了2338元，累计攒了391573元
这是第332周，这周攒了2345元，累计攒了393918元
这是第333周，这周攒了2352元，累计攒了396270元
这是第334周，这周攒了2359元，累计攒了398629元
这是第335周，这周攒了2366元，累计攒了400995元
这里只打印了部分结果，从结果上来看只需要 335 周的时间，也就是六年半的时间，这么一看好像我离买车的目标还是很好实现的，毕竟实际情况这六年我的收入不断增长的。
原题链接：leetcode.com/problems/ca…
您的支持是我最大的动力
