题目描述
示例1
输入：
drop table if exists `employees` ;
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
INSERT INTO employees VALUES(10001,'1953-09-02','Georgi','Facello','M','1986-06-26');
INSERT INTO employees VALUES(10002,'1964-06-02','Bezalel','Simmel','F','1985-11-21');
INSERT INTO employees VALUES(10003,'1959-12-03','Parto','Bamford','M','1986-08-28');
INSERT INTO employees VALUES(10004,'1954-05-01','Chirstian','Koblick','M','1986-12-01');
INSERT INTO employees VALUES(10005,'1955-01-21','Kyoichi','Maliniak','M','1989-09-12');
INSERT INTO employees VALUES(10006,'1953-04-20','Anneke','Preusig','F','1989-06-02');
INSERT INTO employees VALUES(10007,'1957-05-23','Tzvetan','Zielinski','F','1989-02-10');
INSERT INTO employees VALUES(10008,'1958-02-19','Saniya','Kalloufi','M','1994-09-15');
INSERT INTO employees VALUES(10009,'1952-04-19','Sumant','Peac','F','1985-02-18');
INSERT INTO employees VALUES(10010,'1963-06-01','Duangkaew','Piveteau','F','1989-08-24');
INSERT INTO employees VALUES(10011,'1953-11-07','Mary','Sluis','F','1990-01-22');
复制
输出：
10008|1958-02-19|Saniya|Kalloufi|M|1994-09-15
题解
乍一想可以想出来的解法，也确实通过了 运行时间：15ms 超过64.85% 用Sqlite提交的代码 占用内存：3324KB 超过46.78%用Sqlite提交的代码
SELECT * FROM employees ORDER BY hire_date DESC LIMIT 1;
但是这种解法实际上是不完整的，如果最晚入职员工同时有很多个怎么办？
既然最晚入职，所以hire_date肯定是最大的，可以用hire_date找出来，我们筛选的范围就是SELECT MAX(hire_date) FROM employees，我们筛选的条件就是WHERE hire_date IN (SELECT MAX(hire_date) FROM employees)
运行时间：13ms 超过77.91% 用Sqlite提交的代码 占用内存：3320KB 超过61.30%用Sqlite提交的代码
SELECT * FROM employees
WHERE hire_date IN (SELECT MAX(hire_date) FROM employees);
