数组转换

将数组：[['a', 'b'], ['n', 'm'], ['0', '1']]
转换为：["an0", "an1", "am0", "am1", "bn0", "bn1", "bm0", "bm1"]

二进制

an0 => 0 - 0 - 0;
an1 => 0 - 0 - 1;
am0 => 0 - 1 - 0;
am1 => 0 - 1 - 1;
bn0 => 1 - 0 - 0;
bn1 => 1 - 0 - 1;
bm0 => 1 - 1 - 0;
bm1 => 1 - 1 - 1;

let clapArr = [['a', 'b'], ['n', 'm'], ['0', '1']], newArray = [], newClapArr = [];
// 8 = Math.pow(clapArr[0].length,clapArr.length)
for (let i = 0; i < 8; i++) {
    let newStr = i.toString(2).length < 2 ?
        '00' + i.toString(2) :
        i.toString(2).length < 3 ?
            '0' + i.toString(2) :
            i.toString(2);
    newArray.push(newStr);
}
console.log(newArray);// ['000', '001', '010', '011', '100', '101', '110', '111'];

for (let i = 0; i < newArray.length; i++) {
    let str = '';
    newArray[i].split('').forEach((key, ind) => {
        clapArr.forEach((item, index) => {
            index == ind ? str += item[key] : null;
        });
    });
    newClapArr.push(str);
}
console.log(newClapArr);//['an0', 'an1', 'am0', 'am1', 'bn0', 'bn1', 'bm0', 'bm1']