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下边是String 的equels 源码方法
/**
* Compares this string to the specified object. The result is {@code
* true} if and only if the argument is not {@code null} and is a {@code
* String} object that represents the same sequence of characters as this
* object.
*
* @param anObject
* The object to compare this {@code String} against
*
* @return {@code true} if the given object represents a {@code String}
* equivalent to this string, {@code false} otherwise
*
* @see #compareTo(String)
* @see #equalsIgnoreCase(String)
*/
public boolean equals(Object anObject) {
if (this == anObject) {
return true;
}
if (anObject instanceof String) {
String anotherString = (String)anObject;
int n = count;
if (n == anotherString.count) {
char v1[] = value;
char v2[] = anotherString.value;
int i = offset;
int j = anotherString.offset;
while (n-- != 0) {
if (v1[i++] != v2[j++])
return false;
}
return true;
}
}
return false;
}
介绍：
- 1.判断是否等于当前
- 2.判断类型
- 3.转类型
- 4.获取长度 判断长度
- 5.获取 当前和传入值得value 转成char数组
- 6.获取抵消的首索引
- 7.循环判断所有的char字符
- 8.以上每一项不相等都返回false
-
下边是HashMap equels 的源码
public final boolean equals(Object o) {
if (!(o instanceof Map.Entry))
return false;
Map.Entry e = (Map.Entry)o;
Object k1 = getKey();
Object k2 = e.getKey();
if (k1 == k2 || (k1 != null && k1.equals(k2))) {
Object v1 = getValue();
Object v2 = e.getValue();
if (v1 == v2 || (v1 != null && v1.equals(v2)))
return true;
}
return false;
}
介绍：
- 1.判断类型是否属于map.Entry
- 2.转类型
- 3.获取当前key 和 传来值得key
- 4.要求key相对或 本身不等于null 并且 当前key 等于传来的 key
- 5.判断 本身value等于传来value 或 本身不等于 null 并且 本身value equest 传来vlaue
-
Object 的equest
/**
* Indicates whether some other object is "equal to" this one.
* <p>
* The <code>equals</code> method implements an equivalence relation
* on non-null object references:
* <ul>
* <li>It is <i>reflexive</i>: for any non-null reference value
* <code>x</code>, <code>x.equals(x)</code> should return
* <code>true</code>.
* <li>It is <i>symmetric</i>: for any non-null reference values
* <code>x</code> and <code>y</code>, <code>x.equals(y)</code>
* should return <code>true</code> if and only if
* <code>y.equals(x)</code> returns <code>true</code>.
* <li>It is <i>transitive</i>: for any non-null reference values
* <code>x</code>, <code>y</code>, and <code>z</code>, if
* <code>x.equals(y)</code> returns <code>true</code> and
* <code>y.equals(z)</code> returns <code>true</code>, then
* <code>x.equals(z)</code> should return <code>true</code>.
* <li>It is <i>consistent</i>: for any non-null reference values
* <code>x</code> and <code>y</code>, multiple invocations of
* <tt>x.equals(y)</tt> consistently return <code>true</code>
* or consistently return <code>false</code>, provided no
* information used in <code>equals</code> comparisons on the
* objects is modified.
* <li>For any non-null reference value <code>x</code>,
* <code>x.equals(null)</code> should return <code>false</code>.
* </ul>
* <p>
* The <tt>equals</tt> method for class <code>Object</code> implements
* the most discriminating possible equivalence relation on objects;
* that is, for any non-null reference values <code>x</code> and
* <code>y</code>, this method returns <code>true</code> if and only
* if <code>x</code> and <code>y</code> refer to the same object
* (<code>x == y</code> has the value <code>true</code>).
* <p>
* Note that it is generally necessary to override the <tt>hashCode</tt>
* method whenever this method is overridden, so as to maintain the
* general contract for the <tt>hashCode</tt> method, which states
* that equal objects must have equal hash codes.
*
* @param obj the reference object with which to compare.
* @return <code>true</code> if this object is the same as the obj
* argument; <code>false</code> otherwise.
* @see #hashCode()
* @see java.util.Hashtable
*/
public boolean equals(Object obj) {
return (this == obj);
}
- 这个相对比较简单，直接比较对象和本身也就是比较内存中所指向的位置
-
HashTable equels
// Comparison and hashing
/**
* Compares the specified Object with this Map for equality,
* as per the definition in the Map interface.
*
* @param o object to be compared for equality with this hashtable
* @return true if the specified Object is equal to this Map
* @see Map#equals(Object)
* @since 1.2
*/
public synchronized boolean equals(Object o) {
if (o == this)
return true;
if (!(o instanceof Map))
return false;
Map<K,V> t = (Map<K,V>) o;
if (t.size() != size())
return false;
try {
Iterator<Map.Entry<K,V>> i = entrySet().iterator();
while (i.hasNext()) {
Map.Entry<K,V> e = i.next();
K key = e.getKey();
V value = e.getValue();
if (value == null) {
if (!(t.get(key)==null && t.containsKey(key)))
return false;
} else {
if (!value.equals(t.get(key)))
return false;
}
}
} catch (ClassCastException unused) {
return false;
} catch (NullPointerException unused) {
return false;
}
return true;
}
public boolean equals(Object o) {
if (!(o instanceof Map.Entry))
return false;
Map.Entry e = (Map.Entry)o;
return (key==null ? e.getKey()==null : key.equals(e.getKey())) &&
(value==null ? e.getValue()==null : value.equals(e.getValue()));
}
在hashtable的源码中发现俩个equels 不过大部分都用的第一个
实现步骤也是和hashmap很相似
- 1.判断是否是当前
- 2.判断是否是属于map类型
- 3.转类型
- 4.比大小
- 5.获取一个迭代器
- 6.获取每一个 Map.Entry<K,V> e = i.next(); 对象
- 7.获取value key
- 8.比较 value 在比较key 有一项不相等直接返回false
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Integer equels
/**
* Compares this object to the specified object. The result is
* <code>true</code> if and only if the argument is not
* <code>null</code> and is an <code>Integer</code> object that
* contains the same <code>int</code> value as this object.
*
* @param obj the object to compare with.
* @return <code>true</code> if the objects are the same;
* <code>false</code> otherwise.
*/
public boolean equals(Object obj) {
if (obj instanceof Integer) {
return value == ((Integer)obj).intValue();
}
return false;
}
/**
* Constructs a newly allocated <code>Integer</code> object that
* represents the specified <code>int</code> value.
*
* @param value the value to be represented by the
* <code>Integer</code> object.
*/
public Integer(int value) {
this.value = value;
}
剩下的基本类型也都和Integer差不多
- 1.确定当前类型
- 2.比较
- 3.((Integer)obj).intValue();就是当前对象的value看源码就了解了
ok 到这里就了解java 中几乎全部的equels的实现方式了
