打包和解包
def f(x):
return x**2 x**3
f(3) #返回一个元组（9，27）
numbers =[1,2,3]
names =["xiaoming","xiaohong","xiaobai"]
a = list(zip(numbers,names))
# 得到一个列表，列表元素为元组：[（1,"xiaoming"）,(2,"xiaohong"),(3,"xiaobai"),]
for number,name in a:
print(number,name)
