如何能够清除aud脚本？

--//发现自己写的清除aud脚本通用性不好,每次都要修改,写一个通用脚本.而且一些服务器有多个实例的情况. --//编写脚本如下:

cat /usr/local/bin/purge_oracle_aud.sh ! /bin/bash purge oracle audit log odebug=${ODEBUG:-0}

if (( $# < 1 )) then

echo "arguments is insufficiency , argumentN = oracle_sid N>=1"
exit  1

fi

for i in "$@" do

if [ -d /u01/app/oracle/admin/${i}/adump/ ]
then
        echo
        echo "start purge oracle audit ${i} at : " $(/bin/date +'%Y/%m/%d %T')
        /usr/bin/find /u01/app/oracle/admin/${i}/adump/ -mtime +30  -name "${i}_ora_*.aud" -print -delete
        echo "end   purge oracle auditwww.cungun.com ${i} at : " $(/bin/date +'%Y/%m/%d %T')
        echo
else
        echo "/u01/app/oracle/admin/${i}/adump/ directory is not exist"
        exit 2
fi

done

chmod 700 /usr/local/bin/purge_oracle_aud.sh --//还是通用性不好,没有利用环境变量$ORACLE_BASE,先暂时这样没时间.

2.加入crontab页游脚本，如果相对electron有更多直观理解的, 也可以参考:

www.cungun.com

cat /etc/cron.d/ntp 34 6 * root /usr/local/bin/purge_oracle_aud.sh dbcndg2 >> /var/log/purge_oracle_aud.log 2>&1 --//每天6:34分执行.

3.修改/etc/logrotate.d/oracle,加入如下:

grep -v "^#" /etc/logrotate.d/oracle /var/log/purge_oracle_aud.log {

size=20M rotate 5 copytruncate compress notifempty missingok }