<script>
var a = 1111111111111119
var b = 9999999999999998
//求c,c=a+b
let stra = a.toString()//将Number类型转化为String
let strb = b.toString()//将Number类型转化为String
var JW = 0 //定义变量为零,变量代表进位数值
var C = '' //定义空的字符串,用于字符串的拼接
//首先对比那个字符串长,并将两个字符串补为相同长度
if (stra.length >= strb.length) {
stra = stra.padStart(stra.length + 1, '0')
strb = strb.padStart(stra.length, '0')
} else {
stra = stra.padStart(strb.length + 1, '0')
strb = strb.padStart(strb.length, '0')
}
//两字符串长度相同,从右向左遍历两个字符串
for (let i = stra.length - 1
console.log('字符A--->' + stra[i])
console.log('字符B--->' + strb[i])
//将遍历的的第一位字符转化为Number进行运算
Numc = Number(stra[i]) + Number(strb[i]) + JW
//将运算结果除10取整,该整数与下遍历的相加数相加
var JW = parseInt(Numc / 10)
//将运算结果除10取余,余数为各位的数值
var QY = Numc - JW * 10
console.log('进位' + JW)
console.log('取余' + QY)
var C = QY.toString() + C
console.log('字符C--->' + C)
console.log('-----------------------------')
}
</script>