描述
Given an integer n, add a dot (".") as the thousands separator and return it in string format.
Example 1:
Input: n = 987
Output: "987"
Example 2:
Input: n = 1234
Output: "1.234"
Example 3:
Input: n = 123456789
Output: "123.456.789"
Example 4:
Input: n = 0
Output: "0"
Example 5:
Note:
0 <= n < 2^31
解析
根据题意，就是讲数字 n ，转换成字符串，然后从后往前，每隔三位用点隔开，然后返回新的字符串即可。
解答
class Solution(object):
def thousandSeparator(self, n):
"""
:type n: int
:rtype: str
"""
s = str(n)
res = []
for i in range(len(s), -1, -3):
tmp = s[max(0, i - 3):i]
if tmp:
res.insert(0, tmp)
return ".".join(res)
运行结果
Runtime: 12 ms, faster than 94.03% of Python online submissions for Thousand Separator.
Memory Usage: 13.4 MB, less than 38.06% of Python online submissions for Thousand Separator.
原题链接：leetcode.com/problems/th…
您的支持是我最大的动力
