leetcode 1630. Arithmetic Subarrays(python)

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描述

A sequence of numbers is called arithmetic if it consists of at least two elements, and the difference between every two consecutive elements is the same. More formally, a sequence s is arithmetic if and only if s[i+1] - s[i] == s[1] - s[0] for all valid i.

For example, these are arithmetic sequences:

1, 3, 5, 7, 9
7, 7, 7, 7
3, -1, -5, -9

The following sequence is not arithmetic:

1, 1, 2, 5, 7

You are given an array of n integers, nums, and two arrays of m integers each, l and r, representing the m range queries, where the ith query is the range [l[i], r[i]]. All the arrays are 0-indexed.

Return a list of boolean elements answer, where answer[i] is true if the subarray nums[l[i]], nums[l[i]+1], ... , nums[r[i]] can be rearranged to form an arithmetic sequence, and false otherwise.

Example 1:

Input: nums = [4,6,5,9,3,7], l = [0,0,2], r = [2,3,5]
Output: [true,false,true]
Explanation:
In the 0th query, the subarray is [4,6,5]. This can be rearranged as [6,5,4], which is an arithmetic sequence.
In the 1st query, the subarray is [4,6,5,9]. This cannot be rearranged as an arithmetic sequence.
In the 2nd query, the subarray is [5,9,3,7]. This can be rearranged as [3,5,7,9], which is an arithmetic sequence.	

Example 2:

Input: nums = [-12,-9,-3,-12,-6,15,20,-25,-20,-15,-10], l = [0,1,6,4,8,7], r = [4,4,9,7,9,10]
Output: [false,true,false,false,true,true]

Note:

n == nums.length
m == l.length
m == r.length
2 <= n <= 500
1 <= m <= 500
0 <= l[i] < r[i] < n
-105 <= nums[i] <= 105

解析

根据题意,l[i] 和 r[i] 分别是组成 nums 子数组的左索引和右索引,所以只要同时取得 l[i] 和 r[i] 从 nums 中截取得到子数组,并且对其进行是否为等差序列的判断,最后将布尔结果放入 res 中即可,遍历得到所有的子数组对所有的子数组进行判断后即可得到 res 。

解答

 class Solution(object):
    def checkArithmeticSubarrays(self, nums, l, r):
        """
        :type nums: List[int]
        :type l: List[int]
        :type r: List[int]
        :rtype: List[bool]
        """
        res = []
        for i in range(len(l)):
            l_index = l[i]
            r_index = r[i]
            tmp = nums[l_index:r_index+1]
            tmp.sort()
            if(len(tmp)==2):
                res.append(True)
                continue
            distance = tmp[1]-tmp[0]
            for j in range(2, len(tmp)):
                if distance != tmp[j]-tmp[j-1]:
                    res.append(False)
                    break
                elif j==len(tmp)-1:
                    res.append(True)
        return res       	      
		

运行结果

Runtime: 168 ms, faster than 93.02% of Python online submissions for Arithmetic Subarrays.
Memory Usage: 13.4 MB, less than 86.05% of Python online submissions for Arithmetic Subarrays.

原题链接:leetcode.com/problems/ar…

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