Xcode命令行工具允许您从终端使用模拟器。
您可以启动模拟器、触发通用链接等。
其中一项命令允许您向 iOS 模拟器发送推送通知：
$ xcrun simctl push --help
Send a simulated push notification
Usage: simctl push <device> [<bundle identifier>] (<json file> | -)
bundle identifier
The bundle identifier of the target application
If the payload file contains a 'Simulator Target Bundle' top-level key this parameter may be omitted.
If both are provided this argument will override the value from the payload.
json file
Path to a JSON payload or '-' to read from stdin. The payload must:
- Contain an object at the top level.
- Contain an 'aps' key with valid Apple Push Notification values.
- Be 4096 bytes or less.
Only application remote push notifications are supported. VoIP, Complication, File Provider, and other types are not supported.
该命令要求您传递几个参数：
<device>Simply set this to booted to use the open simulator. You can also use a device identifier which you could get with the xcrun simctl list devices | grep Booted command.<bundle identifier>将此设置为要测试推送通知的应用程序的捆绑标识符。<json file>这应该指向磁盘上包含推送通知详细信息的JSON文件。您还可以使用stdin提供JSON内容。 执行示例如下：
$ xcrun simctl push booted com.example.app payload.json
Notification sent to 'com.example.app'
