1 求一个数的阶乘之和
def fec(n):
x = 1
for i in range(n,0,-1):
x *= i
return x
def fec_add(n):
y = 0
for i in range(n,0,-1):
y += fec(i)
return y
print(fec_add(5**))
函数内存地址
参考网址： www.pythontotur.com
def func1(a):
print (id(a)) #4547574560
a = 100
print (id(a)) #4547574560
x = 1
print(id(x)) #44547577728
func1(x)
print(x) #1
print(id(x)) #4547574560
#--------------------------------------------------------------------------------------
def func1(a):
print (id(a)) #140337923450752
a[0] = 100
print (id(a)) #140337923450752
x = [1,2,3,4,5,6]
print(id(x)) #140337923450752
func1(x)
print(x) #[100, 2, 3, 4, 5, 6]
print(id(x)) #140337923450752
回调函数
from even import *
#中间函数
#接受一个生成偶数的函数作为参数
#返回一个奇数
def getOddNumber(k, getEvenNumber):
return 1 + getEvenNumber(k)
#起始函数，这里是程序的主函数
def main():
k = 1
#当需要生成一个2k+1形式的奇数时
i = getOddNumber(k, double)
print(i)
#当需要一个4k+1形式的奇数时
i = getOddNumber(k, quadruple)
print(i)
#当需要一个8k+1形式的奇数时
i = getOddNumber(k, lambda x: x * 8)
print(i)
if __name__ == "__main__":
main()
continue & break
product_scores = [99,6,7,33,4,99,89]
for i in range(len(product_scores)):
if procuct_scores[i] >= 75:
continue
print("第{0}个产品，分数为{1},不合格".format(i,product_scores[i]))
product_scores = [99,6,7,33,4,99,89]
count = 0
for i in product_scores:
if procuct_scores[i] < 75:
i+=1
if i ==2:
print("本批次产品不合格")
else:
print(“本批次产品合格”）
while 循环
not_read = ["红楼梦","s水浒传","三国志","西游记"]
have_read =[]
while not_read:
book = not_read.pop()
have_read.appdend(book)
print("我已经读过{}了".format(book))
