代码演练 下拉菜单的显示与隐藏
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<title>Title</title>
<script src="js/jquery-3.6.0.js"></script>
<style>
* {
margin: 0;
padding: 0;
}
.menu > li {
float: left;
width: 100px;
height: 50px;
text-align: center;
line-height: 50px;
border: 1px solid black;
list-style: none;
margin-left: -1px;
position: relative;
}
.content {
position: absolute;
top: 50px;
left: 0;
background-color: blue;
width: 100px;
display: none;
}
.content ul {
background-color: red;
}
.content li {
list-style: none;
background-color: yellow;
}
</style>
</head>
<body>
<div class="contianer">
<ul class="menu">
<li>功能1
<div class="content">
<ul>
<li>1</li>
<li>2</li>
<li>3</li>
<li>4</li>
<li>5</li>
<li>6</li>
</ul>
</div>
</li>
<li>功能2
<div class="content">
<ul>
<li>1</li>
<li>2</li>
<li>3</li>
<li>4</li>
<li>5</li>
<li>6</li>
</ul>
</div>
</li>
<li>功能3</li>
<li>功能4</li>
</ul>
</div>
<script>
$(function () {
// 移上去显示
$(".menu > li").mouseover(function () {
$(this).children("div.content").show();
})
// 移出去隐藏
$(".menu>li").mouseout(function () {
$(this).children("div.content").hide();
})
});
</script>
</body>
</html>
