题目描述

题解
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val
* TreeNode left
* TreeNode right
* TreeNode() {}
* TreeNode(int val) { this.val = val
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val
* this.left = left
* this.right = right
* }
* }
*/
// 递归
// 本题和【剑指offer】27. 二叉树的镜像 一模一样
// 执行用时:0 ms, 在所有 Java 提交中击败了100.00%的用户
// 内存消耗:36.2 MB, 在所有 Java 提交中击败了5.38%的用户
class Solution {
public TreeNode invertTree(TreeNode root) {
if (root == null)
return root
swap(root)
invertTree(root.left)
invertTree(root.right)
return root
}
public void swap(TreeNode root) {
TreeNode temp = root.left
root.left = root.right
root.right = temp
}
}