请写一个 min 函数,要求 min(numbers) 能返回数组 numbers 中的最小数字
let min = (numbers) => numbers[0] < numbers[1] ? numbers[0] : numbers[1]
let min = (numbers) => {
if(numbers.length > 2){
return min(
[numbers[0],min(numbers.slice(1))]
)
}else{
return Math.min.apply(null,numbers)
}
return numbers
}
min([1,3,4,2,9,7,6])
请写出一个 sort 函数,要求 sort(numbers) 能返回一个把 numbers 从小到大排列的数组
let minIndex = (numbers) =>{
let index = 0
for(let i = 1 ; i < numbers.length ; i++){
if(numbers[i] < numbers[index]){
index = i
}
}
return index
}
let sort = (numbers) => {
if(numbers.length > 2){
let index = minIndex(numbers)
let min = numbers[index]
numbers.splice(index,1)
return [min].concat(sort(numbers))
}else{
return numbers[0] < numbers[1] ? numbers : numbers.reverse()
}
}
sort([1,3,4,2,9,7,6])
let sort = (numbers) =>{
for(let i = 0;i < numbers.length -1;i++){
console.log('----')
console.log(`i:${i}`)
let index = minIndex(numbers.slice(i))+i
console.log(`index:${index}`)
console.log(`min:${numbers[index]}`)
if(index!==i){
swap(numbers,index,i)
}
console.log(`swap ${index}:${i}`)
}
return numbers
}
let swap = (array , i , j) => {
let temp = array[i]
array[i] = array[j]
array[j] = temp
}
let minIndex = (numbers) => {
let index = 0
for(let i =1;i<numbers.length;i++){
if(numbers[i] < numbers[index]){
index = i
}
}
return index
}
快速排序
let quickSort = (arr) => {
if(arr.length <= 1){return arr;}
let pivotIndex = Math.floor(arr.length / 2);
let pivot = arr.splice(pivotIndex , 1)[0];
let left = []
let right = []
for(let i = 0 ; i < arr.length ; i++){
if(arr[i] < pivot){ left.push(arr[i])
}else{ right.push(arr[i])}
}
return quickSort(left).concat([pivot],quickSort(right))
}

归并排序
let mergeSort = arr => {
if(arr.length===1){return arr}
let left = arr.slice(0,Math.floor(arr.length / 2))
let right = arr.slice(Math.floor(arr.length / 2))
return merge(mergeSort(left),mergeSort(right))
}
let merge = (a,b) =>{
if(a.length === 0){return b}
if(b.length === 0){return a}
return (a[0] > b[0]) ? [b[0]].concat(merge(a,b.slice(1))) : [a[0]].concat(merge(a.slice(1),b))
}
计数排序
let countSort = arr =>{
let hashTable = {}
let max = 0
let result = []
for(let arr[i] = 0 ;i<arr.length; i++){
if(!(i in hashTable)){
hashTable[arr[i]] = 1
}else{
hashTable[arr[i]] += 1
}
if(arr[i] > max){max = arr[i]}
}
for(let j = 0;j<=max; j++){
if(j in hashTable){
for(let i = 0; i<hashTable[j]; i++){
result.push(j)
}
}
}
return result
}
countSort([5,2,3,9,7,6])