75.新编号查询案例(分类查询)

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/*--查询新编号的示例

	要求:
	按id前4位分组,查询出最小一组的缺号,如果没有,则用最大组的id+1

*/

--测试数据
create table tb(id int)
insert tb select 10010001
union all select 10010002
union all select 10010003
union all select 10010004
union all select 10010005
--union all select 10020001
union all select 10020002
union all select 10020003
union all select 10020004
union all select 10030001
go

--查询处理1(最小编号为:xxxx0001的处理)
select 新id=left(id,4)+right(10001+right(a.id,4),4)
from(
	select id=isnull(min(a.id),(select max(id) from tb))
	from(
		select id from tb
		union all
		select distinct left(id,4)+'0000' from tb 
	)a left join(
		select id=max(id) from tb group by left(id,4)
	)b on a.id=b.id
	where b.id is null and 	not exists(
		select * from tb where id=left(a.id,4)+right(10001+right(a.id,4),4))
)a

--查询处理2(最小编号为表中每组的最小编号)
select 新id=left(id,4)+right(10001+right(a.id,4),4)
from(
	select id=isnull(min(a.id),(select max(id) from tb))
	from tb a left join(
		select id=max(id) from tb group by left(id,4)
	)b on a.id=b.id
	where b.id is null and 	not exists(
		select * from tb where id=left(a.id,4)+right(10001+right(a.id,4),4))
)a
go

--删除测试
drop table tb

/*--测试结果

新id              
---------------- 
10020001

(所影响的行数为 1 行)


新id              
---------------- 
10030002

(所影响的行数为 1 行)
--*/