LeetCode 7. Reverse Integer

127 阅读1分钟

Given a signed 32-bit integer x, return x with its digits reversed. If reversing x causes the value to go outside the signed 32-bit integer range [-231, 231 - 1], then return 0.

Assume the environment does not allow you to store 64-bit integers (signed or unsigned).

Example 1:

Input: x = 123
Output: 321

Example 2:

Input: x = -123
Output: -321

Example 3:

Input: x = 120
Output: 21

Example 4:

Input: x = 0
Output: 0

Constraints:

-231 <= x <= 231 - 1
class Solution {
public:
    int reverse(int x) {
        int ans = 0;
        while (x != 0) {
            if (ans > INT_MAX / 10 || (ans == INT_MAX / 10 && x % 10 > INT_MAX % 10))
                return 0;  // overflow
            if (ans < INT_MIN / 10 || (ans == INT_MIN / 10 && x % 10 < INT_MIN % 10))
                return 0;  // underflow
            ans = ans * 10 + x % 10;
            x /= 10;
      }
      return ans;
    }
};