请写出一个 sort 函数,要求 sort (numbers) 能返回一个把 numbers 从小到大排列的数组
var sort = (numbers) => {
if(numbers.length >2){
let index = minIndex(numbers)
let min = numbers[index]
numbers.splice(index,1);
return [min].concat(sort(numbers))
}else{
return numbers[0] < numbers[1] ? numbers : numbers.reverse()
}
}
let minIndex = (numbers) =>
numbers.indexOf(min(numbers))
请写一个 min 函数,要求 min (numbers) 能返回数组 numbers 中的最小数字。
let min = (numbers) => {
if(numbers.length > 2){
return min(
[numbers[0], min(numbers.slice(1))]
)
}else{
return Math.min.apply(null, numbers)
}
}