- 取小于100的数 filter :
let newNums = nums.filter(function (n) {
return n < 100
})
console.log(newNums);
for :
let newNums = []
for (let n of nums) {
if (n < 100) {
newNums.push(n)
}
}
- 将所有小于100的数字进行转化: 全部*2
map :
let new2Nums = newNums.map(function (n) {
return n * 2
})
console.log(new2Nums);
for :
let new2Nums = []
for (let n of newNums) {
new2Nums.push(n * 2)
}
console.log(new2Nums);
3.将所有new2Nums数字相加,得到最终的结果
reduce :
let total = new2Nums.reduce(function (prevalue, n) {
return preValue + n
}, 0)
console.logo(total);
for :
let total = 0
for (let n of new2Nums) {
total += n
}
filter、map、reduce:
let total = nums.filter(function (n) {
return n < 100
}).map(function (n) {
return n * 2
}).reduce(function (prevValue, n) {
return prevValue + n
}, 0)
console.log(total);
箭头函数:
let total = nums.filter(n => n < 100).map(n => n * 2).reduce((pre, n) => pre + n);
console.log(total);