空格
- 在Swift中,运算符不能直接跟在变量或常量的后面。
String
- 字符串分割数组 -- 基于空格
let fullName = "First Last" let fullNameArr = fullName.split(separator: " ") print(" \(fullNameArr[0]) lastName: \(fullNameArr[1])") - 字符串遍历
let str = "测试测试ceshi" // 正序遍历 for tmp in str { print("\(tmp)") } // 逆序遍历 for tmp in str.reversed() { print("\(tmp)") } // 基于EnumeratedSequence的遍历 for (i,ch) in str.enumerated() { print("\(i) + \(ch)") } - 字符串拼接
str.append("test")
Array
-
有序存储同一类型的多个值,不去重
-
创建数组
var someArray = [Int]() var someArray0: [Int] = [] var someArray1 = [Int] (repeating: 0, count: 10) var someArray2: [Int] = [10, 20, 30] -
修改数组
someArray.append(12) someArray += [40] someArray[1] = 0 -
遍历数组
for item in someArray { print(item) } // 根据索引和值遍历 for (index, item) in someArray.enumerated() { print("\(index) : \(item)") } -
合并数组
someArray = someArray1 + someArray2 someArray.isEmpty //判断数组是否为空
Dictionary
-
无序存储相通类型的数据
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创建字典
var someDict = [String: Int] () var someDict0: [Int: String] = [:] var someDict1: [Int: String] = [1: "one", 2: "two"] -
修改字典
// 获取字典的值 var someVar = someDict1[3] // key 不存在则添加值,key 存在则修改 var oldVal = someDict.updateValue(12, forKey: "test") someDict["test0"] = 1 // 如果key存在,则返回移除的值,不存在则返回nil var removedValue = someDict.removeValue(forKey: "test") someDict["test0"] = nil -
字典遍历
for (key, value) in someDict { print("\(key) : \(value)") } // index 字典索引,value 是(key,value)对 for (index, value) in someDict.enumerated() { print("\(index) : \(value)") } -
获取字典的
key和value数组someDict.keys someDict.values