queryURLparams 工作中常常会遇到获取url地址参数的例子，记录一下封装好的方法，好记性不如烂笔头

	const url = 'http://www.baidu.com/index.html?lx=1&name=zhangsan&age=10#box';
    function queryUrlParams(url){
        // 1 获取？和 # 后面的信息
        let askIn = url.indexOf('?');
        let wellIn = url.indexOf('#');
        let askText ="";
        let wellText = "";
        //  # 不存在
        wellIn===-1?wellIn = url.length:null;
        // ? 存在
        askIn>=0?askText = url.substring(askIn+1,wellIn):null;
        wellText=url.substring(wellIn+1);
        // 获取每一部分信息
        let result ={};
        wellText!==""?result['HASH'] = wellText:null;
        if(askText!==""){
            let ary = askText.split('&');
            ary.forEach(item => {
                let itemAry = item.split('=');
                result[itemAry[0]] = itemAry[1];
            });
        }

        return result;
    }