经典时事件队列题

33.事件队列习题
(思路: 1先执行宏任务，2遇到微任务放微任务队列， 3宏任务执行完，执行一轮微任务， 然后再次轮询执行下一轮1234)
console.log('1');
setTimeout(function() {
    console.log('2');
    process.nextTick(function() {
        console.log('3');
    })
    new Promise(function(resolve) {
        console.log('4');
        resolve();
    }).then(function() {
        console.log('5')
    })
})
process.nextTick(function() {
    console.log('6');
})
new Promise(function(resolve) {
    console.log('7');
    resolve();
}).then(function() {
    console.log('8')
})

setTimeout(function() {
    console.log('9');
    process.nextTick(function() {
        console.log('10');
    })
    new Promise(function(resolve) {
        console.log('11');
        resolve();
    }).then(function() {
        console.log('12')
    })
})
结合上面讲的逻辑 可以分析一波得出最后答案是1，7，6，8，2，4，3，5，9，11，10，12

第二道：
console.log(1);

setTimeout(() => {
  console.log(2);
  Promise.resolve().then(() => {
    console.log(3)
  });
});

new Promise((resolve, reject) => {
  console.log(4)
  resolve(5)
}).then((data) => {
  console.log(data);
  Promise.resolve().then(() => {
    console.log(6)
  }).then(() => {
    console.log(7)
    setTimeout(() => {
      console.log(8)
    }, 0);
  });
})
setTimeout(() => {
  console.log(9);
})
console.log(10);
1 4 10 5 6 7 2 3 9 8



//请写出输出内容，提示：await后的语句会放到微任务的队列头部，并且await>then>setimeout回调
async function async1() {
    console.log('async1 start');
    await async2();
    console.log('async1 end');
}
async function async2() {
	console.log('async2');
}

console.log('script start');

setTimeout(function() {
    console.log('setTimeout');
}, 0)

async1();

new Promise(function(resolve) {
    console.log('promise1');
    resolve();
}).then(function() {
    console.log('promise2');
});
console.log('script end');


/*
script start
async1 start
async2
promise1
script end
async1 end
promise2
setTimeout
*/