选择排序
let swap= (array,i,j) => {
let temp = array[i]
array[i] = array[j]
array[j] = temp
}
let minIndex = (numbers) => {
let index = 0
for(let i=1;i<numbers.length;i++){
if(numbers[i]<numbers[index]){
index = i
}
}
return index
}
let sort = (numbers) => {
for(let i=0;i<numbers.length-1;i++){
let index=minIndex(numbers.slice(i))+i
if(index!==i){swap(numbers,index,i)}
}
return numbers
}
let numbers = [88,77,11,111,333]
sort(numbers)
快速排序
let quickSort = arr => {
if(arr.length<=1){return arr}
let pivotIndex = Math.floor(arr.length/2)
let pivot = arr.splice(pivotIndex,1)[0];
let left = []
let right = []
for(let i=0;i<arr.length;i++){
if(arr[i]<pivot){left.push(arr[i])}
else{right.push(arr[i])}
}
return quickSort(left).concat([pivot],quickSort(right))
}
let numbers = [88,77,11,111,333]
quickSort(numbers)
归并排序
let mergeSort = arr => {
if(arr.length===1){return arr}
let left = arr.slice(0,Math.floor(arr.length/2))
let right = arr.slice(Math.floor(arr.length/2))
return merge(mergeSort(left),mergeSort(right))
}
let merge = (a,b) =>{
if(a.length===0) return b
if(b.length===0) return a
return a[0]>b[0]?
[b[0]].concat(merge(a,b.slice(1))):
[a[0]].concat(merge(b,a.slice(1)))
}
let numbers = [123,234,333,11]
mergeSort(numbers)
计数排序
let countSort = arr => {
let hashTable = {},max = 0,result = []
for(let i=0;i<arr.length;i++){
if(!(arr[i] in hashTable)){
hashTable[arr[i]] = 1
}else{
hashTable[arr[i]] += 1
}
if(arr[i]>max){max=arr[i]}
}
for(let j=0;j<=max;j++){
if(j in hashTable){
for(let i=0;i<hashTable[j];i++){
result.push(j)
}
}
}
return result
}
let numbers = [23,435,6546,11,2]
countSort(numbers)