设计一个支持 push,pop,top 操作,并能在常数时间内检索到最小元素的栈。
push(x) -- 将元素 x 推入栈中。 pop() -- 删除栈顶的元素。 top() -- 获取栈顶元素。 getMin() -- 检索栈中的最小元素。
class MinStack {
private Stack<Integer> stack;
private Stack<Integer> stackMin;
/** initialize your data structure here. */
public MinStack() {
stack = new Stack();
stackMin = new Stack();
}
public void push(int x) {
stack.push(x);
if(stackMin.isEmpty() || stackMin.peek()>x){
stackMin.push(x);
}else{
stackMin.push(stackMin.peek());
}
}
//peek() 加remove()
public void pop() {
if(!stack.isEmpty()){
stack.pop();
stackMin.pop();
}
}
//
public int top() {
if(!stack.isEmpty()){
return stack.peek();
}
throw new RuntimeException("stack is empty");
}
public int getMin() {
if(!stackMin.isEmpty()){
return stackMin.peek();
}
throw new RuntimeException("stack is empty");
}
}
/**
- Your MinStack object will be instantiated and called as such:
- MinStack obj = new MinStack();
- obj.push(x);
- obj.pop();
- int param_3 = obj.top();
- int param_4 = obj.getMin(); */