阅读源码后,发现Koa的洋葱模型,很简单

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原先对koa的认知停留在使用上面,最近在阅读koa2的源码,发现koa2的洋葱模型实现原理很简单,核心代码在koa-compose里面,竟然只有几十行:


function compose (middleware) {
  if (!Array.isArray(middleware)) throw new TypeError('Middleware stack must be an array!')
  for (const fn of middleware) {
    if (typeof fn !== 'function') throw new TypeError('Middleware must be composed of functions!')
  }

  return function (context, next) {
    // last called middleware #
    let index = -1
    return dispatch(0)
    function dispatch (i) {
      if (i <= index) return Promise.reject(new Error('next() called multiple times'))
      index = i
      let fn = middleware[i]
      if (i === middleware.length) fn = next
      if (!fn) return Promise.resolve()
      try {
        return Promise.resolve(fn(context, dispatch.bind(null, i + 1)));
      } catch (err) {
        return Promise.reject(err)
      }
    }
  }
}

其中,compose函数,负责处理注册的所有中间件,我们使用以下方式注册中间件(middleware)

app.use(async (ctx, next)=>{
    // code
    await next();
    // code
})
app.use(async (ctx, next)=>{
    // code
    await next();
    // code
})

那么,koa2是如何处理注册的中间件,并实现它的洋葱模型呢? koa2会将注册的所有中间件函数,放在数组middleware中,使用koa-compose,处理moddleware这个数组。

下面就是对compose函数的解析。


function compose (middleware) {
//  容错判断,如果middleware不是数组,或者元素不是函数,则抛异常
  if (!Array.isArray(middleware)) throw new TypeError('Middleware stack must be an array!')
  for (const fn of middleware) {
    if (typeof fn !== 'function') throw new TypeError('Middleware must be composed of functions!')
  }

// compose函数最终返回一个闭包函数
  return function (context, next) {
    // last called middleware #
    let index = -1
    return dispatch(0)
    // 使用递归操作,将各个function作为前一个function的next参数传递过去
    function dispatch (i) {
      if (i <= index) return Promise.reject(new Error('next() called multiple times'))
      index = i
      let fn = middleware[i]
      if (i === middleware.length) fn = next
      if (!fn) return Promise.resolve()
      try {
        return Promise.resolve(fn(context, dispatch.bind(null, i + 1)));
      } catch (err) {
        return Promise.reject(err)
      }
    }
  }
}