【Golang语言】LeetCode 867. Transpose Matrix 矩阵转置

矩阵转置，A[i][j] 变成A[j][i] 比较简单，直接上代码了。

func transpose(A [][]int) [][]int {
	B := make([][]int, len(A[0]))
	for i := 0; i < len(A[0]); i++ {
		B[i] = make([]int, len(A))
		for j := 0; j < len(A); j++ {
			B[i][j] = A[j][i]
		}
	}
	return B
}