js中将数组中的数字进行翻转 Fundamentalproblems 2019-06-19 108 阅读1分钟 var sum = new Array(10,20,30,40,50,60,70) for(var i=0; i<sum.length/2; i++){ var temp temp = sum[i] sum[i]=sum[sum.length-1-i] sum[sum.length-1-i]=temp } console.log(sum) document.write(sum)