172. Factorial Trailing Zeroes

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Share Given an integer n, return the number of trailing zeroes in n!.

Example 1:

Input: 3 Output: 0 Explanation: 3! = 6, no trailing zero. Example 2:

Input: 5 Output: 1 Explanation: 5! = 120, one trailing zero. Note: Your solution should be in logarithmic time complexity.

思路：比如100！，只要查看5的个数，因为2肯定是够得

代码:python3

class Solution:
    def trailingZeroes(self, n: int) -> int:
        zeroCount = 0
        while n > 0:
            n=int(n/5)
            zeroCount += n
        return zeroCount