给定一个未排序的整数数组,找出其中没有出现的最小的正整数。
示例 1:
输入: [1,2,0]
输出: 3
示例 2:
输入: [3,4,-1,1]
输出: 2
示例 3:
输入: [7,8,9,11,12]
输出: 1class Solution:
def firstMissingPositive(self, nums: List[int]) -> int:
N = len(nums)
for i in range(N):
if nums[i] <= 0:
nums[i] = N + 1
ni = 0
for i in range(N):
ni = abs(nums[i]) - 1
if ni < N:
nums[ni] = -abs(nums[ni])
for i in range(N):
if nums[i] > 0:
return i + 1
return N + 1