【题目描述】

【代码思路】 这个太过简单,基础数据结构算法,不多叙述
【源代码】 c++:
class Solution {
public:
int search(vector<int>& nums, int target) {
int left=0;
int right=nums.size()-1;
int mid=0;
while(left<=right){
mid=(left+right)/2;
if(nums[mid]==target){
return mid;
}else if(nums[mid]>target){
right=mid-1;
}else{
left=mid+1;
}
}
return -1;
}
};
python3
class Solution:
def search(self, nums: List[int], target: int) -> int:
left=0
right=len(nums)-1
while left <= right:
mid = (left + right)//2
if nums[mid]==target:
return mid
elif nums[mid] < target:
left = mid + 1
else:
right = mid - 1
return -1