给定一个 32 位有符号整数，将整数中的数字进行反转。

public class reveserInt {
    public static void main(String[] args) {
        int reverse = reverse(-99);
        System.out.println(reverse);
    }

    public static int reverse(int num) {
        String str = "";
        int temp;
        if (num < 0) {
            str = "-";
        }
        temp = Math.abs(num);
        while (temp != 0) {
            int i = temp % 10;
            temp /= 10;
            str += (i + "");
        }
        int result = 0;
        try {
            result = Integer.parseInt(str);
        } catch (NumberFormatException e) {
            e.printStackTrace();
            return 0;
        }
        if (result > Math.pow(2, 31) - 1 || result < Math.pow(-2, 31)) {
            return 0;
        }
        return result;
    }
}