Reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123, return -321 Note: The input is assumed to be a 32-bit signed integer. Your function should return 0 when the reversed integer overflows. 将一个整数中的数字进行颠倒，当颠倒后的整数溢出时，返回 0 (标记为 32 位整数)。

分析

通过取余得到最后一位，循环，对于溢出进行判断即可

代码

public int reverse(int x) {
        int result = 0;

	    while(x != 0) {
	    	int tail = x % 10;
	    	int newResult = result * 10 + tail;
	    	if((newResult-tail)/10 != result)
	    		return 0;
	    	result = newResult;
	    	x = x/10;
	    }
	    return result;
    }