var ajax = new XMLHttpRequest(); ajax.open('post','juejin.cn',true); ajax.setRequestHeader('content-type','application/x-www-form-urlencoded'); ajax.send("aid=2608&avatar=p3-juejin.byteimg.com"); ajax.onreadystatechange = function (){ if(ajax.readyState==4&&ajax.status==200){ var c = ajax.responseText; console.log(c) } }