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- 请问一下 arr1 和 arr2 怎么比较才能提示 code b 数量不一致,求算法
list arr1 = [{code:'a',count:2},{code:'b',count:3}]
list arr2 = [{code:'a',name:'A'},{code:'a',name:'A1'},{code:'b',name:'B1'}]//三行数据,默认一行的数量就是一个展开评论点赞 - 请问一下 arr1 和 arr2 怎么比较才能提示 code b 数量不一致,求算法list arr1 = [{code:'a',count:2},{code:'b',count:3}]
list arr2 = [{code:'a',name:'A'},{code:'a',name:'A1'},{code:'b',name:'B1'}]//三行数据,默认一行的数量就是一个展开评论点赞 - 请问一下,这个怎么分组求和啊,结果a:8,b:8,两行数据let arr = [{ code: "a", count: "3" },
{ code: "a", count: "5" },
{ code: "b", count: "6" },
{ code: "b", count: "2" }]展开6点赞